document.write( "Question 91244: During rush hour, Fernando can drive 20 miles using the side roads in the same time that it takes to travel 15 miles on the freeway. If Fernando's rate on the side roads is 9 mi/h faster than his rate on the freeway, find his rate on the side roads. \n" ); document.write( "
Algebra.Com's Answer #66446 by ankor@dixie-net.com(22740)\"\" \"About 
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During rush hour, Fernando can drive 20 miles using the side roads in the same time that it takes to travel 15 miles on the freeway. If Fernando's rate on the side roads is 9 mi/h faster than his rate on the freeway, find his rate on the side roads.
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\n" ); document.write( "let s = speed on side roads
\n" ); document.write( "then
\n" ); document.write( "(s-9) = speed on the freeway
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\n" ); document.write( "Write a time equation: Time = Dist/speed
\n" ); document.write( "Sideroad time = Freeway time
\n" ); document.write( "\"20%2Fs\" = \"15%2F%28%28s-9%29%29\"
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\n" ); document.write( "Cross multiply
\n" ); document.write( "20(s-9) = 15s
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\n" ); document.write( "20s - 180 = 15s
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\n" ); document.write( "20s - 15s = +180
\n" ); document.write( ":
\n" ); document.write( "5s = 180
\n" ); document.write( ":
\n" ); document.write( "s = 180/5
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\n" ); document.write( "s = 36 mph speed on the side-roads
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\n" ); document.write( "Check solution using the time
\n" ); document.write( "20/36 = 5/9
\n" ); document.write( "15/27 = 5/9 \n" ); document.write( "
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