document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1048878>Question 1048878</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the following five-number summary, find the IQR.<BR>\n" );
document.write( "2.9, 5.7, 10.0, 13.2, 21.1\r<BR>\n" );
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document.write( "The answer is 7.5, but how do I get that? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664433 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664433\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The IQR is the difference between the third quartile and the first quartile<BR>\n" );
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document.write( "minimum is 2.9 <BR>\n" );
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document.write( "median is the number which half of numbers are below and half of the numbers are above  (2.9, 5.7, 10.0, 13.2, 21.1) = 10.0<BR>\n" );
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document.write( "first quartile is the median of the data below the overall median = (2.9 + 5.7) / 2 = 4.3<BR>\n" );
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document.write( "third quartile is the median of the data above the overall median = (13.2 + 21.1) / 2 = 17.15<BR>\n" );
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document.write( "IQR = 17.15 - 4.3 = 12.85<BR>\n" );
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