document.write( "Question 91488: Solving a word promblem using a quadratic equation with rational roots\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 1 yd less than three times ite width and the area of the rectangle is 24yd^2. Find the diminsions.
\n" ); document.write( "

Algebra.Com's Answer #66442 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let W = the width of the rectangle and L = the length.
\n" ); document.write( "The problem description tells you that the length, L, is (=) 1 yd less than three times its width (L = 3W-1).
\n" ); document.write( "You also know that the area, A = 24 sq.yds.
\n" ); document.write( "Starting with the formula for the area of a rectangle: A = L*W
\n" ); document.write( "Making the appropriate substitutions into the formula, you get:
\n" ); document.write( "\"%283W-1%29%28w%29+=+24\" Simplifying this:
\n" ); document.write( "\"3W%5E2-W+=+24\" Subtract 24 from both sides.
\n" ); document.write( "\"3W%5E2-W-24+=+0\" You can solve this quadratic equation by factoring.
\n" ); document.write( "\"%283w%2B8%29%28W-3%29+=+0\" Apply the zero products principle:
\n" ); document.write( "\"3W%2B8+=+0\" or \"W-3+=+0\", so...
\n" ); document.write( "\"3W%2B8+=+0\" Subtract 8 from both sides.
\n" ); document.write( "\"3W+=+-8\" Divide both sides by 3.
\n" ); document.write( "\"W+=+-8%2F3\" Discard this solution a negative width is not meaningful.\r
\n" ); document.write( "\n" ); document.write( "\"W-3+=+0\" Add 3 to both sides.
\n" ); document.write( "\"W+=+3\" The width is 3 yards.
\n" ); document.write( "\"L+=+3W-1\"
\n" ); document.write( "\"L+=+3%283%29-1\"
\n" ); document.write( "\"L+=+9-1\"
\n" ); document.write( "\"L+=+8\" The length is 8 yards.\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "\"A+=+L%2AW\"
\n" ); document.write( "\"A+=+8%283%29\"
\n" ); document.write( "\"A+=+24\"sq.yds.
\n" ); document.write( "
\n" );