document.write( "Question 91488: Solving a word promblem using a quadratic equation with rational roots\r
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document.write( "The length of a rectangle is 1 yd less than three times ite width and the area of the rectangle is 24yd^2. Find the diminsions. \n" );
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Algebra.Com's Answer #66441 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Area of a rectangle=Length times Width or A=L*W\r \n" ); document.write( "\n" ); document.write( "Let W=width of the rectangle\r \n" ); document.write( "\n" ); document.write( "Then Length (L)=3W-1\r \n" ); document.write( "\n" ); document.write( "And Area= 24 yd^2 =W*(3W-1)=3W^2-W So our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "3W^2-W=24 subtract 24 from both sides\r \n" ); document.write( "\n" ); document.write( "3W^2-W-24=24-24 simplifying, we get:\r \n" ); document.write( "\n" ); document.write( "3W^2-W-24=0 quadratic in standard form. We'll solve using the quadratic formula\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "A=24=3*8 \n" ); document.write( "24=24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |