document.write( "Question 1048822: Hi there, I could use some help on this please!\r
\n" ); document.write( "\n" ); document.write( "Assume that you toss a fair six-faced die two times.
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\n" ); document.write( "(a) (1 pt) How many possible outcomes are in the sample space? Explain your answer.\r
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\n" ); document.write( "\n" ); document.write( "(b) (1 pt) What is the probability that you get a number greater than 3 at the first toss? (Show work and write the answer in simplest fraction form)\r
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\n" ); document.write( "\n" ); document.write( "(c) (2 pts) What is the probability that the sum of the two tosses is at least 9? (Show work and write the answer in simplest fraction form)\r
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\n" ); document.write( "\n" ); document.write( "(d) (2 pts) What is the probability that the sum of the two tosses is at least 9, given that you get a number greater than 3 in the first toss? (Show work and write the answer in simplest fraction form)\r
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\n" ); document.write( "\n" ); document.write( "(e) (2 pts) If event A is “Getting a number greater than 3 in the first toss” and event B is “The sum of two tosses is at least 9”. Are event A and event B independent? Use statistical concept and mathematical expression to justify your answer. \r
\n" ); document.write( "\n" ); document.write( "I appreciate any help you can offer!
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Algebra.Com's Answer #664400 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi  
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document.write( "Assume that you toss a fair six-faced die two times
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document.write( "(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)\r
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document.write( "(2,1) (2,2) (2,3) (2,4) (2,5) (2,6) \r
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document.write( "(3,1) (3,2) (3,3) (3,4) (3,5) ,6 \r
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document.write( "(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) \r
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document.write( "(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) \r
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document.write( "(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)\r
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document.write( "a) 36 Outcomes
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document.write( "b) P(3 first) = 6(underlined)/36 = 1/6\r
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document.write( "-----------------
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document.write( "___1_2_3__4__5__6
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document.write( "1|_2_3_4__5__6__7
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document.write( "2|_3_4_5__6__7__8
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document.write( "3|_4_5_6__7__8__9
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document.write( "4|_5_6_7__8__9_10
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document.write( "5|_6_7_8__9_10_11
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document.write( "6|_7_8_9_10_11_12
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document.write( "c) P( Sum >=9) = 10/36  | Yes, good counting! P = 5/18
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document.write( "d) P(A|B) = P(A and B)/P(B)
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document.write( "P( Sum >=9) | 3 first) =  = 1/6
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document.write( "count them -  only one 3 first AND >=9 (highlighted)
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document.write( "e) P(A|B) = P(A and B)/P(B)
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document.write( "P( Sum >=9) |first > 3)  = 9/18 = 1/2  Count them
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document.write( "Conditional Probability:  Two events are not Independent 
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document.write( "Event: where Sum >=9, depends on the parameters put of the first draw
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