document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91112>Question 91112</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3(2y-1)=7-2(y-3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66438 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66438\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3(2y-1)= 7 - 2(y-3)<BR>\n" );
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document.write( "Multiply what's inside the brackets and you have:<BR>\n" );
document.write( "6y - 3 = 7 - 2y + 6: \"neg outside the brackets, changes signs inside the brackets\"<BR>\n" );
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document.write( "6y + 2y - 3 = 7 + 6; added 2y to both sides to isolate y on the left<BR>\n" );
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document.write( "8y = 13 + 3; added 3 to both sides to isolate y on the left<BR>\n" );
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document.write( "8y = 16<BR>\n" );
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document.write( "y = 16/8; divide both sides by 8<BR>\n" );
document.write( "y = 2<BR>\n" );
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document.write( "Check solution in original equation; substitute +2 for x:<BR>\n" );
document.write( "3(2y-1)= 7 - 2(y-3)<BR>\n" );
document.write( "3(2(2)- 1) = 7 - 2(2 - 3)<BR>\n" );
document.write( "3(4 - 1) = 7 - 2(-1); minus times a minus is plus<BR>\n" );
document.write( "3 * 3 = 7 + 2<BR>\n" );
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