document.write( "Question 1048802: Please help me with this question.\r
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document.write( "2. The rate of decay of a radioactive substance is 0.1% per year.
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document.write( "(a) Find the half-life of the substance.
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document.write( "(b) How long would it take until only 1/2 of the amount remains?
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document.write( "(c) How long would it take until 2/3 of the original amount decays?
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document.write( "(d) How much of the 10 mg sample of the substance will remain after
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document.write( "5,000 years? \n" );
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Algebra.Com's Answer #664372 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The rate of decay of a radioactive substance is 0.1% per year. \n" ); document.write( "----- \n" ); document.write( "(a) Find the half-life of the substance. \n" ); document.write( "A(t) = Ao(0.999)^t \n" ); document.write( "------- \n" ); document.write( "(b) How long would it take until only 1/2 of the amount remains?\r \n" ); document.write( "\n" ); document.write( "(1/2)Ao = Ao(0.999)^t \n" ); document.write( "0.999^t = (1/2) \n" ); document.write( "t = log(0.5)/log(0.999) = 692.8 years \n" ); document.write( "------------------------------------------------------ \n" ); document.write( "(c) How long would it take until 2/3 of the original amount decays? \n" ); document.write( "t = log(2/3)/log(0.999) = 405.26 years \n" ); document.write( "---------------------------------------- \n" ); document.write( "(d) How much of the 10 mg sample of the substance will remain after \n" ); document.write( "5,000 years? \n" ); document.write( "A(5000) = 10*0.999^5000 \n" ); document.write( "A(5000) = 0.0672 mg \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( " \n" ); document.write( " |