document.write( "Question 1048774: A drink is one-third syrup and the rest water. If six ounces of water were added, it would become 20% sure. How many ounces of total liquid (water plus syrup) were in the original mixture? \n" ); document.write( "

Algebra.Com's Answer #664360 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = total ounces of
\n" ); document.write( "liquid in original mixture
\n" ); document.write( " $\"+%281%2F3%29%2Ax+\"$ = ounces of syrup
\n" ); document.write( "in original mixture
\n" ); document.write( " $\"+%282%2F3%29%2Ax+\"$ = ounces of water
\n" ); document.write( "in original mixture
\n" ); document.write( "-------------------------------
\n" ); document.write( " $\"+%28+%281%2F3%29%2Ax+%29+%2F+%28+x+%2B+6+%29+=+.2+\"$
\n" ); document.write( " $\"+%281%2F3%29%2Ax+=+.2%2A%28+x+%2B+6+%29+\"$
\n" ); document.write( " $\"+x+=+.6%2A%28+x+%2B+6+%29+\"$
\n" ); document.write( " $\"+x+=+.6x+%2B+3.6+\"$
\n" ); document.write( " $\"+.4x+=+3.6+\"$
\n" ); document.write( " $\"+x+=+36%2F4+\"$
\n" ); document.write( " $\"+x+=+9+\"$
\n" ); document.write( "9 ounces of liquid were in original mixture
\n" ); document.write( "----------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+%281%2F3%29%2Ax+%29+%2F+%28+x+%2B+6+%29+=+.2+\"$
\n" ); document.write( " $\"+%28+%281%2F3%29%2A9+%29+%2F+%28+9+%2B+6+%29+=+.2+\"$
\n" ); document.write( " $\"+3+%2F+15+=+.2+\"$
\n" ); document.write( " $\"+3+=+.2%2A15+\"$
\n" ); document.write( " $\"+3+=+3+\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );