document.write( "Question 1048785: Find the Equation of a Tangent Line to f(x) = 3x^2 - 11x + 23 at the point (1,15)\r
\n" ); document.write( "\n" ); document.write( "I've worked out using the 1st derivative as hinted and would appreciate any checking if this is correct, many thanks.\r
\n" ); document.write( "\n" ); document.write( "1st derivative: d/dx [f(x)]
\n" ); document.write( "f'(x)= d/dx [3x^2 - 11x + 23]
\n" ); document.write( "=3* d/dx [x^2] - 11* d/dx [x] + d/dx [23] (using power rule)
\n" ); document.write( "=3*2x - 11*1 + 0
\n" ); document.write( "=6x - 11\r
\n" ); document.write( "\n" ); document.write( "Plug x=1 into f'(x)
\n" ); document.write( "f'(1) = 6(1) - 11
\n" ); document.write( "= -5\r
\n" ); document.write( "\n" ); document.write( "Using point-slope form
\n" ); document.write( "y-y1 = m(x-x1)
\n" ); document.write( "y-15 = -5(x-1)
\n" ); document.write( "y=-5x+5+15
\n" ); document.write( "Ans: y=-5x+20
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Algebra.Com's Answer #664356 by robertb(5830)\"\" \"About 
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Your solution and final answer are correct. Good job. \n" ); document.write( "
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