document.write( "Question 1048781: Instead of finding even or odd consecutive integers we could also look for integersthat differ by a number other than 2. Find three numbers that each differ by 3 such that 5 times the largest integer is equal to three times the smallest increased by 5 times the middle \n" ); document.write( "
Algebra.Com's Answer #664354 by Theo(13342) You can put this solution on YOUR website! let x be the smallest number. \n" ); document.write( "let x + 3 be the middle number. \n" ); document.write( "let x + 6 be the largest number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5 * (x + 6) = 3 * x + 5 * (x + 3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this equation says that 5 times the largest number is equal to 3 times the smallest number plus 5 times the middle number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify the equation to get 5x + 30 = 3x + 5x + 15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "combine like terms to get 5x + 30 = 8x + 15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 15 from both sides of the equation and subtract 5x from both sides of the equation to get 30 - 15 = 8x - 5x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "combine like terms to get 15 = 3x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get x = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 5, x + 3 = 8, and x + 6 = 11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the difference between each succeeding number is 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5 * 11 = 55\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 * 5 + 5 * 8 = 15 + 40 = 55\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solution looks good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the smallest number is 5. \n" ); document.write( "the middle number is 8. \n" ); document.write( "the largest number is 11. \n" ); document.write( " \n" ); document.write( " |