document.write( "Question 1048781: Instead of finding even or odd consecutive integers we could also look for integersthat differ by a number other than 2. Find three numbers that each differ by 3 such that 5 times the largest integer is equal to three times the smallest increased by 5 times the middle \n" ); document.write( "
Algebra.Com's Answer #664354 by Theo(13342)\"\" \"About 
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let x be the smallest number.
\n" ); document.write( "let x + 3 be the middle number.
\n" ); document.write( "let x + 6 be the largest number.\r
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\n" ); document.write( "\n" ); document.write( "your equation is:\r
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\n" ); document.write( "\n" ); document.write( "5 * (x + 6) = 3 * x + 5 * (x + 3)\r
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\n" ); document.write( "\n" ); document.write( "this equation says that 5 times the largest number is equal to 3 times the smallest number plus 5 times the middle number.\r
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\n" ); document.write( "\n" ); document.write( "simplify the equation to get 5x + 30 = 3x + 5x + 15\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get 5x + 30 = 8x + 15\r
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\n" ); document.write( "\n" ); document.write( "subtract 15 from both sides of the equation and subtract 5x from both sides of the equation to get 30 - 15 = 8x - 5x\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get 15 = 3x\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = 5\r
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\n" ); document.write( "\n" ); document.write( "when x = 5, x + 3 = 8, and x + 6 = 11\r
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\n" ); document.write( "\n" ); document.write( "the difference between each succeeding number is 3.\r
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\n" ); document.write( "\n" ); document.write( "5 * 11 = 55\r
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\n" ); document.write( "\n" ); document.write( "3 * 5 + 5 * 8 = 15 + 40 = 55\r
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\n" ); document.write( "\n" ); document.write( "solution looks good.\r
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\n" ); document.write( "\n" ); document.write( "the smallest number is 5.
\n" ); document.write( "the middle number is 8.
\n" ); document.write( "the largest number is 11.
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