document.write( "Question 1048750: Hi,
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document.write( "I can't find answer to this question.\r
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document.write( "\"A freight train leaves a station travelling at 30 mph. A passenger train leaves 1 hours later travelling at 50 mph. At what time will the passenger train overtake the freight train? \" \n" );
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Algebra.Com's Answer #664322 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A freight train leaves a station travelling at 30 mph. A passenger train leaves 1 hours later travelling at 50 mph. \n" ); document.write( " At what time will the passenger train overtake the freight train? \n" ); document.write( ": \n" ); document.write( "When the pass train overtakes the freight, they will have traveled the same distance \n" ); document.write( "let t = traveling time of the freight \n" ); document.write( "then \n" ); document.write( "(t-1) = traveling time of the pass train \n" ); document.write( ": \n" ); document.write( "Write a distance equation, dist = speed * time \n" ); document.write( ": \n" ); document.write( "Pass train dist = freight dist \n" ); document.write( "50(t-1) = 30t \n" ); document.write( "50t - 50 = 30t \n" ); document.write( "50t - 30t = 50 \n" ); document.write( "20t = 50 \n" ); document.write( "t = 50/20 \n" ); document.write( "t = 2.5 hrs from the time the freight leaves \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this, find the actual distance \n" ); document.write( "30 * 2.5 = 75 mi \n" ); document.write( "50 * 1.5 = 75 mi \n" ); document.write( " |