document.write( "Question 1048679: the perimeter of a rectangular pool is 380 yards. if the length is 20 yards less than twice the width.find the length and the width \n" ); document.write( "

Algebra.Com's Answer #664257 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+w+\"$ = the width in yards
\n" ); document.write( " $\"+2w+-+20+\"$ = the length in yards
\n" ); document.write( "--------------------------------
\n" ); document.write( "Using the formula for perimeter:
\n" ); document.write( " $\"+2w+%2B+2%2A%28+2w+-+20+%29+=+380+\"$
\n" ); document.write( " $\"+2w+%2B+4w+-+40+=+380+\"$
\n" ); document.write( " $\"+6w+=+420+\"$
\n" ); document.write( " $\"+w+=+70+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+2w+-+20+=+2%2A70+-+20+\"$
\n" ); document.write( " $\"+2w+-+20+=+120+\"$
\n" ); document.write( "-------------------------
\n" ); document.write( "The width is 70
\n" ); document.write( "The length is 120
\n" ); document.write( "-------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+P+=+2%2A70+%2B+2%2A120+\"$
\n" ); document.write( " $\"+P+=+140+%2B+240+\"$
\n" ); document.write( " $\"+P+=+380+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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