document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1048646>Question 1048646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A contractor has submitted bids for two state construction projects. The probability that he will win any contract is 0.25. Find the probability that:<BR>\n" );
document.write( "a) He will win both contracts<BR>\n" );
document.write( "b) He will win neither contract<BR>\n" );
document.write( "c) He will win exactly one contract </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664246 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> probability(P) that the contractor wins a contract = 0.25 = 1/4<BR>\n" );
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document.write( "probability(P) that the contractor does not win a contract = 1 - 0.25 = 3/4<BR>\n" );
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document.write( "a) P (winning both contracts ) = (1/4) * (1/4) = 1/16<BR>\n" );
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document.write( "b) P ( does not win a contract ) = (3/4) * (3/4) = 9/16<BR>\n" );
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document.write( "c) P ( wins one contract ) = (1/4) * (3/4) = 3/16<BR>\n" );
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