document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13284>Question 13284</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In any triangle, the sum of the measures of the angles is 180 degrees. In triangle ABC, angle A is three times as large as angle B and also 16 degress larger thans angle c. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6642 by </B><A HREF=/tutors/aboutme.mpl?userid=bam878s><B>bam878s(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bam878s><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6642\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From this we have <BR>\n" );
document.write( "A=3B and A=C+16<BR>\n" );
document.write( "So B=A/3 and C=A-16<BR>\n" );
document.write( "We know 180=A+B+C<BR>\n" );
document.write( "So, 180=A + (A/3) + (A-16)<BR>\n" );
document.write( "180=A(1+(1/3)+1)-16<BR>\n" );
document.write( "180=A(7/3)-16<BR>\n" );
document.write( "196=A(7/3)<BR>\n" );
document.write( "A=84<BR>\n" );
document.write( "So B=A/3=84/3=28<BR>\n" );
document.write( "and C=A-16=84-16=68<BR>\n" );
document.write( "Check 68+28+84=180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );