document.write( "Question 91465: I ask the wrong question, sorry
\n" ); document.write( "factoring a quadratic with leading cofficient greater than one
\n" ); document.write( "2z^2-z-6
\n" ); document.write( "Thank you for the help, I would never get these with out this help \n" ); document.write( "

Algebra.Com's Answer #66418 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Factor:
\n" ); document.write( " $\"2z%5E2-z-6\"$
\n" ); document.write( "First, find the factors of the leading coefficient (that's the 2).
\n" ); document.write( "There is only one possibility and that's 1*2
\n" ); document.write( "So you can start by writing (2x + m)(x + n)
\n" ); document.write( "Now m*n must be equal to -6 (the consatnt term in the quadratic equation) so the possibilities are:
\n" ); document.write( "m*n = -6 So you know that m and n will have opposite signs
\n" ); document.write( "-1*6 = -6 (m = -1 and n = 6)
\n" ); document.write( "1*(-6) = -6 (m = 1 and n = -6)
\n" ); document.write( "-2*3 = -6 (m = -2 and n = 3)
\n" ); document.write( "2*(-3) = -6 (m = 2 and n = -3)
\n" ); document.write( "You also know that 2(n)+m = -1 (This is the coefficient of the z-term).
\n" ); document.write( "So we try:
\n" ); document.write( "(2z+3)(z-2) Using FOIL to multiply, we get:
\n" ); document.write( " $\"2z%5E2-4z%2B3z-6\"$ Combining like-terms, we get:
\n" ); document.write( " $\"2z%5E2-z-6\"$
\n" ); document.write( "So the factors are:
\n" ); document.write( "(2z+3)(z-2) \n" ); document.write( "

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