document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1048512>Question 1048512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 6 feet shorter than its length. If its perimeter is 82 feet, what is its width?\r<BR>\n" );
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document.write( "please show steps thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664165 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664165\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length=x<BR>\n" );
document.write( "width=x-6<BR>\n" );
document.write( "perimeter is 2l+2w=82 or l+w=41, dividing everything by 2<BR>\n" );
document.write( "x+(x=6)=41<BR>\n" );
document.write( "2x-6=41<BR>\n" );
document.write( "add 6 to both sides<BR>\n" );
document.write( "2x=47<BR>\n" );
document.write( "x=23.5 feet, dividing by 2<BR>\n" );
document.write( "x-6=17.5 feet<BR>\n" );
document.write( "Their sum is 41 feet.<BR>\n" );
document.write( "Double it for the perimeter, and that is 82 feet. </SPAN>\n" );
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