document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1048319>Question 1048319</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A web developer is creating a website. The page will have a frame along its top and left sides showing the name of the site and links to different parts of the site. These frames will take up one third of the computer screen. If the computer screen is 7 in by 11 in, what will the width of the frames be? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664138 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664138\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of the screen is 7 x 11=77<BR>\n" );
document.write( "Let n be the width of the frames. Then:<BR>\n" );
document.write( "(7-n)(11-n)=(2x77)/3<BR>\n" );
document.write( "231-54n+3nē=154<BR>\n" );
document.write( "3nē-54n+77=0<BR>\n" );
document.write( "Using the quadratic formula; we get n=16.439 and 1.561. Throwing out the higher number, we get the width of the frame to be 1.561 inches. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );