document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91442>Question 91442</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0536944733/algebrahomeworkh>Introductory & Intermediate ALGEBRA</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this question.\r<BR>\n" );
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document.write( " Find the equation of each line. Write the equation using function notation.\r<BR>\n" );
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document.write( "Through (-4,8); perpendicular to 2x - 3y = 1\r<BR>\n" );
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document.write( "  Thanks.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66408 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2X-3Y=1<BR>\n" );
document.write( "-3Y=-2X+1<BR>\n" );
document.write( "Y=-2X/-3+1/-3<BR>\n" );
document.write( "Y=2X/3-1/3 THIS LINE HAS A SLOPE OF 2/3 SO A LINE WHICH IS PERPENDICULAR HAS A SLOPE OF -3/2. NOW USING THIS SLOPE & THE POINT (-4,8) IN THE LINE EQUATION <BR>\n" );
document.write( "[Y=mX+b] WE GET<BR>\n" );
document.write( "8=-3/2*-4+b<BR>\n" );
document.write( "8=12/2+b<BR>\n" );
document.write( "8=6+b<BR>\n" );
document.write( "b=8-6<BR>\n" );
document.write( "b=2 THUS THE EQUATION OF THIS LINE IS:<BR>\n" );
document.write( "Y=-3X/2+2 </SPAN>\n" );
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