document.write( "Question 1048417: FACTOR EACH COMPLETELY\r
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Algebra.Com's Answer #664052 by Edwin McCravy(20059)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"24xy%2B25y%5E2-20x-30y%5E3\"\r\n" );
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document.write( "Try to factor by grouping as they are arranged,\r\n" );
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document.write( "\"cross%28y%2824x%2B25y%29-10%282x-3y%5E2%29%29\"\r\n" );
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document.write( "No, that doesn't give us a common factor.\r\n" );
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document.write( "Rearrange by swapping the two middle terms:\r\n" );
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document.write( "\"24xy-20x%2B25y%5E2-30y%5E3\"\r\n" );
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document.write( "Try to factor by grouping as they are arranged\r\n" );
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document.write( "\"cross%284x%286y-5%29%2B5y%5E2%285-6y%29%29\"\r\n" );
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document.write( "Now we see we should have swapped the last two terms\r\n" );
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document.write( "\"24xy-20x-30y%5E3%2B25y%5E2\"\r\n" );
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document.write( "\"4x%286y-5%29-5y%5E2%286y-5%29\"\r\n" );
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document.write( "Now we have a common factor (6y-5)\r\n" );
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document.write( "\"%286y-5%29%284x-5y%5E2%29\"\r\n" );
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document.write( "Edwin
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