document.write( "Question 91453: Lane invested $14000 part at 15% and part at 2%. If the total interest at the end of the year is $1060 how much did she invest at 15%. My dear friends, if anyone can help I would be so grateful. \n" ); document.write( "
Algebra.Com's Answer #66404 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! LET X BE THE AMOUNT INVESTED @ 15% & 14000-X BE THE AMOUNT INVESTED @ 2%. \n" ); document.write( ".15X+.02(14000-X)=1060 \n" ); document.write( ".15X+280-.02X=1060 \n" ); document.write( ".13X=1060-280 \n" ); document.write( ".13X=780 \n" ); document.write( "X=780/.13 \n" ); document.write( "X=6000 ANSWE RFOR AMOUNT INVESTED @ 15%. \n" ); document.write( "PROOF \n" ); document.write( ".15*6000+.02*8000=1060 \n" ); document.write( "900+160=1060 \n" ); document.write( "1060=1060 \n" ); document.write( " |