document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1048453>Question 1048453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to write an equation in slope intercept form for the line that passes through the given point and is Perpendicular to the graph of the given equations. I need to show work. (-2,-2),y=-1/3x=9<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #664020 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=664020\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Line thru(-2,-2),perpendicular to y=-1/3x+9 , m = (-1/3)<BR>\n" );
document.write( "Perpendicular Line m = 3/1 (negative reciprocal of (-1/3))<BR>\n" );
document.write( "Using point-slope form, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+-+y%5B1%5D+=+highlight_green%28m%29%28x+-+x%5B1%5D%29 ALIGN=MIDDLE  ALT=\"y+-+y%5B1%5D+=+highlight_green%28m%29%28x+-+x%5B1%5D%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "y + 2 = 3(x+2)<BR>\n" );
document.write( "y = 3x + 4 (in slope intercept form) </SPAN>\n" );
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