document.write( "Question 91456: The length of a rectangle is 1 cm more than 5 times its width. If the area of the rectangle is 89 cm2, find the dimensions of the rectangle to the nearest thousandth. I don't understand where to even start. \n" ); document.write( "
Algebra.Com's Answer #66400 by checkley71(8403)\"\" \"About 
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W=WIDTH
\n" ); document.write( "L=LENGTH L=5W+1
\n" ); document.write( "AREA=L*W
\n" ); document.write( "89=W(5W+1)
\n" ); document.write( "89=5W^2+W
\n" ); document.write( "5W^2+W-89=0
\n" ); document.write( "USING THE QUADRATIC EQUATION: \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "WE GET
\n" ); document.write( "W=(-1+-SQRT[1^2-4*5*-89])/2*5
\n" ); document.write( "W=(-1+-SQRT[1+1780])/10
\n" ); document.write( "W=(-1+-SQRT1781)/10
\n" ); document.write( "W=(-1+-42.2)/10
\n" ); document.write( "W=(-1+42.2)/10
\n" ); document.write( "W=41.2/10
\n" ); document.write( "W=4.12 ANSWER FOR THE WIDTH
\n" ); document.write( "L=5*4.12+1
\n" ); document.write( "L=20.6+1
\n" ); document.write( "L=21.6
\n" ); document.write( "PROOF
\n" ); document.write( "4.12*21.6=89
\n" ); document.write( "89=89
\n" ); document.write( " \n" ); document.write( "
\n" );