document.write( "Question 91208: A rectangle is 4 times as long as it is wide. A second rectangle is 5 cm longer and 2 cm wider than the first. The area of the second rectangle is 270 square cm greater than the first. What are the dimensions of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #66397 by ankor@dixie-net.com(22740)\"\" \"About 
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Translate each sentence into an equation/expression
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\n" ); document.write( "A rectangle is 4 times as long as it is wide.
\n" ); document.write( "x = width of the 1st rectangle
\n" ); document.write( "then
\n" ); document.write( "4x = length of the 1st rectangle
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\n" ); document.write( "A second rectangle is 5 cm longer and 2 cm wider than the first.
\n" ); document.write( "(4x + 5) = length of the 2nd rectangle
\n" ); document.write( "(x+2) = width of the 2nd rectangle
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\n" ); document.write( "The area of the second rectangle is 270 square cm greater than the first.
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\n" ); document.write( "Area of 2nd rectangle - area of 2st rectangle = 270
\n" ); document.write( "(4x+5)*(x+2) - x(4x) = 270
\n" ); document.write( "(4x^2 + 8x + 5x + 10) - 4x^2 = 270; FOILed (4x+5)(x+2)
\n" ); document.write( "4x^2 + 13x + 10 - 4x^2 = 270;
\n" ); document.write( "13x + 10 = 270; 4x^2's cancel each other
\n" ); document.write( "13x = 270 - 10
\n" ); document.write( "13x = 260
\n" ); document.write( "x = 260/13
\n" ); document.write( "x = 20
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\n" ); document.write( " What are the dimensions of the original rectangle?
\n" ); document.write( "1st rectangle: 4*20 = 80: 80 by 20
\n" ); document.write( "2nd rectangle: 80+5; 20+2; 85 by 22
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\n" ); document.write( "Check solution
\n" ); document.write( "85*22 = 1870
\n" ); document.write( "80*20 = 1600
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\n" ); document.write( "diffence 270
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\n" ); document.write( "How about this? Did I make it understandable to you?
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