document.write( "Question 1048396: A large cooler contains the following drinks: 8 lemonades, 6 Sprites, 13 Cokes, and 5 root beers. You randomly pick two cans, one at a time (without replacement). Compute the following probabilities.\r
\n" ); document.write( "\n" ); document.write( "(a) What is the probability that you get two cans of Sprite?
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\n" ); document.write( "\n" ); document.write( "(b) What is the probability that you do not get two cans of Coke?
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\n" ); document.write( "\n" ); document.write( "(c) What is the probability that you get either two root beers or two lemonades?
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\n" ); document.write( "\n" ); document.write( "(d) What is the probability that you get one can of Coke and one can of Sprite?\r
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\n" ); document.write( "\n" ); document.write( "(e) What is the probability that you get two drinks of the same type?
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Algebra.Com's Answer #663969 by ewatrrr(24785)\"\" \"About 
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32 Total: 8 lemonades, 6 Sprites, 13 Cokes, and 5 root beers
\n" ); document.write( "pick two cans, one at a time (without replacement)
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\n" ); document.write( "The idea is: P = amount of the kind chosen/Total
\n" ); document.write( "Remembering on the second pick one less of both: kind and Total
\n" ); document.write( "a) P(2-S) = (6/32)(5/31)
\n" ); document.write( "b) P(NOT 2 C) = 1 - (13/32)(12/31)
\n" ); document.write( "c) P(2 RB 0r 2L) = (5/32)(4/31)+ (8/32)(7/31)
\n" ); document.write( "e) P = (6/32)(5/31) + (13/32)(12/31) + (5/32)(4/31)+ (8/32)(7/31)
\n" ); document.write( "d) P = (13/32)(6/31) + (6/32)(13/31) (Depends on which kind is picked first)
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