document.write( "Question 1048300: Solve algebraically. How many liters of a 20% salt solution must be added to 60 liters of 40% solution to obtain a solution that is 35% salt? \n" ); document.write( "

Algebra.Com's Answer #663897 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = liters of the 20% solution needed
\n" ); document.write( " $\"+.2x+\"$ = liters of salt in the 20% solution
\n" ); document.write( "-------------------
\n" ); document.write( " $\"+%28+.2x+%2B+.4%2A60+%29+%2F+%28+x+%2B+60+%29+=+.35+\"$
\n" ); document.write( " $\"+%28+.2x+%2B+24+%29+%2F+%28+x+%2B+60+%29+=+.35+\"$
\n" ); document.write( " $\"+.2x+%2B+24+=+.35%2A%28+x+%2B+60+%29+\"$
\n" ); document.write( " $\"+.2x+%2B+24+=+.35x+%2B+21+\"$
\n" ); document.write( " $\"+.15x+=+3+\"$
\n" ); document.write( " $\"+x+=+20+\"$
\n" ); document.write( "20 liters of the 20% solution are needed
\n" ); document.write( "--------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+.2x+%2B+.4%2A60+%29+%2F+%28+x+%2B+60+%29+=+.35+\"$
\n" ); document.write( " $\"+%28+.2%2A20+%2B+.4%2A60+%29+%2F+%28+20+%2B+60+%29+=+.35+\"$
\n" ); document.write( " $\"+%28+4+%2B+24+%29+%2F+80+=+.35+\"$
\n" ); document.write( " $\"+28+=+.35%2A80+\"$
\n" ); document.write( " $\"+28+=+28+\"$
\n" ); document.write( "OK \n" ); document.write( "

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