document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1048281>Question 1048281</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve algebraically.  William is going to hire a snow plowing service. Elizabeth charges an annual fee of $80 plus $5 each time she plows. Jon charges an annual fee of $50 plus $10 each time he plows. How many times would the snow need to be plowed for the cost of both plans to be the same? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #663891 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=663891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let each time s/he plows x<BR>\n" );
document.write( "50+10x = 80+5x subtract 50 and subtract 5x on both sides<BR>\n" );
document.write( "5x = 30<BR>\n" );
document.write( "x = 6 times <BR>\n" );
document.write( "----------------------<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "50+(10*6) = 80+(5*6)<BR>\n" );
document.write( "50+60 = 80+30<BR>\n" );
document.write( "110 = 110 Correct<BR>\n" );
document.write( ":<BR>\n" );
document.write( "John </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );