document.write( "Question 1048277: Amy is twice as old as Jenny. Five years ago, Amy was three times as old as Jenny. Find Jenny's age. \n" ); document.write( "
Algebra.Com's Answer #663884 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Jenny's age=x \n" ); document.write( "Amy is 2x \n" ); document.write( "2x-5=3(x-5). that is five years ago. \n" ); document.write( "distributing \n" ); document.write( "2x-5=3x-15 \n" ); document.write( "moving the numbers and variable to opposite sides \n" ); document.write( "x=10 \n" ); document.write( "Jenny is 10 \n" ); document.write( "Amy is 20 \n" ); document.write( "five years ago, they were 5 and 15 respectively. \n" ); document.write( " |