document.write( "Question 1048277: Amy is twice as old as Jenny. Five years ago, Amy was three times as old as Jenny. Find Jenny's age. \n" ); document.write( "
Algebra.Com's Answer #663884 by Boreal(15235)\"\" \"About 
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Jenny's age=x
\n" ); document.write( "Amy is 2x
\n" ); document.write( "2x-5=3(x-5). that is five years ago.
\n" ); document.write( "distributing
\n" ); document.write( "2x-5=3x-15
\n" ); document.write( "moving the numbers and variable to opposite sides
\n" ); document.write( "x=10
\n" ); document.write( "Jenny is 10
\n" ); document.write( "Amy is 20
\n" ); document.write( "five years ago, they were 5 and 15 respectively.
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