document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91447>Question 91447</A>: <I><SPAN STYLE=\"word-break: break-all;\"> rewrite the equation as a function of x 4x - 10y = 11. thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66388 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66388\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are given the equation:<BR>\n" );
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document.write( "4x - 10y = 11<BR>\n" );
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document.write( "and asked to rewrite it as a function of x.<BR>\n" );
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document.write( "All this requires you to do is to solve the equation for y in terms of x and then replace y<BR>\n" );
document.write( "by the notation f(x).<BR>\n" );
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document.write( "Your first goal is to get the term containing y by itself on one side of the equation<BR>\n" );
document.write( "and everything else on the other side.  Begin by getting rid of the 4x on the left side by<BR>\n" );
document.write( "subtracting 4x from both sides. When you do that the equation becomes:<BR>\n" );
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document.write( "-10y = -4x + 11<BR>\n" );
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document.write( "Now you can solve for y by dividing both sides of this equation by -10 which is the multiplier<BR>\n" );
document.write( "of the y.  Dividing both sides (all terms) by -10 results in the equation becoming:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%28-4%2F-10%29x+%2B+11%2F%28-10%29 ALIGN=MIDDLE  ALT=\"y+=+%28-4%2F-10%29x+%2B+11%2F%28-10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-4%2F-10%29 ALIGN=MIDDLE  ALT=\"%28-4%2F-10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > simplifies to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-2%2F-5%29 ALIGN=MIDDLE  ALT=\"%28-2%2F-5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and the two minus signs cancel so the result is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2F5%29 ALIGN=MIDDLE  ALT=\"%282%2F5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Substituting this makes the equation become:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%282%2F5%29x+%2B+11%2F%28-10%29 ALIGN=MIDDLE  ALT=\"y+=+%282%2F5%29x+%2B+11%2F%28-10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Then the term <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=11%2F%28-10%29 ALIGN=MIDDLE  ALT=\"11%2F%28-10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > involves a division of a negative into a positive. The result<BR>\n" );
document.write( "of this (due to the difference in signs) is a negative. Using this rule results in the<BR>\n" );
document.write( "equation becoming:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%282%2F5%29x+-+%2811%2F10%29 ALIGN=MIDDLE  ALT=\"y+=+%282%2F5%29x+-+%2811%2F10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Now all you have to do is replace \"y\" by \"f(x)\" and the answer to your problem is:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%28x%29+=+%282%2F5%29x+-+11%2F10 ALIGN=MIDDLE  ALT=\"f%28x%29+=+%282%2F5%29x+-+11%2F10\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Hope this helps you to understand how to do problems of this type where you are asked to<BR>\n" );
document.write( "solve for a function of x.<BR>\n" );
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