document.write( "Question 1048271: Solve theproblem using the exponential model and population growth.\r
\n" ); document.write( "\n" ); document.write( "-A researcher is investigating a specimen of bacteria. She finds that the original 1000 bacteria grew to 2,048,000 in 60 hours. How fast does the bacteria (a) double? (b) quadruple?
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Algebra.Com's Answer #663877 by Boreal(15235)\"\" \"About 
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Ce^kt=2048000
\n" ); document.write( "t=60; C=1000
\n" ); document.write( "1000*e^60k=2048000
\n" ); document.write( "e^60k=2048=2^11, after dividing by 1000. 1024 is 2^10, and 2048 is 2^11.
\n" ); document.write( "ln of both sides
\n" ); document.write( "60k=11 ln2
\n" ); document.write( "k=11ln2/60=0.1271
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\n" ); document.write( "Cd=Ce^(0.1271)t
\n" ); document.write( "divide by C, and Cd/C=2, since it is doubling.
\n" ); document.write( "2=e^(0.1271)t
\n" ); document.write( "ln of both sides
\n" ); document.write( "ln2=0.1271 t; ln of e removes it
\n" ); document.write( "0.693=0.1271t
\n" ); document.write( "t=5.45 hours
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\n" ); document.write( "quadruple
\n" ); document.write( "ln 4=0.1271t
\n" ); document.write( "t=ln4/0.127=10.90 hours, or recognize that doubling twice is quadrupling.
\n" ); document.write( "from 1000 to 2048000 is 11 doubling times, and 60/11=5.45
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