document.write( "Question 1048255: I'm having some trouble with this problem and could use some help!\r
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document.write( "Height and weight are two measurements used to track a child’s development. The World Health Organization measures
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document.write( "child development by comparing the weights of children who are the same height and the same gender. In 2009, weights for
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document.write( "all 80 cm girls in the reference population had a mean μ = 10.2 kg and standard deviation σ = 0.8 kg. Weights are normally
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document.write( "distributed. X ~ N(10.2, 0.8). Calculate the z-scores that correspond to the following weights and interpret them.
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document.write( "a. 11 kg
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document.write( "b. 7.9 kg
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document.write( "c. 12.2 kg\r
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document.write( "I appreciate any help you can offer, thanks! \n" );
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Algebra.Com's Answer #663855 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! mean μ = 10.2 kg and standard deviation σ = 0.8 kg. distributed. X ~ N(10.2, 0.8) \n" ); document.write( "*Note: \n" ); document.write( "a. 11 kg, z = .8/.8 = 1 (84% weigh less) \n" ); document.write( "b. 7.9 kg z = -2.3/.8 = -28/8 = -3.5 (Far... left of average(z=0) 98.98% weigh more) \n" ); document.write( "c. 12.2 kg z = 2/.8 = 20/8 = 2.5 (Far right on curve 99.38% weigh less) \n" ); document.write( "| \n" ); document.write( "| \n" ); document.write( "For the normal distribution: Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted. \n" ); document.write( "Area under the standard normal curve to the left of the particular z is P(z) \n" ); document.write( "Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50% to the right \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |