document.write( "Question 1048251: Hi there, If you could help me w/ this problem I would be very grateful for your help!\r
\n" ); document.write( "\n" ); document.write( "Assume the speed of vehicles along a stretch of I-10 has an approximately normal distribution with a mean of 71 mph and a standard deviation of 8 mph.\r
\n" ); document.write( "\n" ); document.write( "a. The current speed limit is 65 mph. What is the proportion of vehicles less than or equal to the speed limit?\r
\n" ); document.write( "\n" ); document.write( "b. What proportion of the vehicles would be going less than 50 mph?\r
\n" ); document.write( "\n" ); document.write( "Any help is appreciated, thanks!
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Algebra.Com's Answer #663848 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
mean of 71 mph and a standard deviation of 8 mph.
\n" ); document.write( "\"z+=blue+%28x+-+mu%29%2Fblue%28sigma%29\"
\n" ); document.write( "a. P(x<= 65) = P(z <= -6/8) = P(z <= -3/4)
\n" ); document.write( "TI syntax is normalcdf(smaller z, larger z)
\n" ); document.write( "normalcdf( ... is a command people using a TI Calculator
\n" ); document.write( "use for finding the area under a standard normal curve
\n" ); document.write( "between two z=values...-9999 used for the far far left z-value
\n" ); document.write( "to give us what we want: area under a standard normal curve for
\n" ); document.write( "a particular z-value, in this case z = -.75 (Area under the curve to left of Blue Line)
\n" ); document.write( "normalcdf(-9999, -.75) = .2266 0r 22.66%
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\n" ); document.write( "\n" ); document.write( "b . P(x<= 50) = P(z <= -21/8)
\n" ); document.write( "normalcdf(-9999, -21/8) = .0043 0r .43%
\n" ); document.write( "One can use table as well to find the z-value
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