document.write( "Question 1048227: Jackson has investments totaling K8, 000 in two accounts – one a savings account paying
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document.write( "6% interest, and the other a premium account paying 9%. If the annual interest from the
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document.write( "two investments was K600, how much did he have invested at each rate? \n" );
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Algebra.Com's Answer #663814 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Let n be the amount invested at 9%. Then: \n" ); document.write( ".09n+.06(8000-n)=600 \n" ); document.write( ".03n+480=600 \n" ); document.write( ".03n=120 \n" ); document.write( "n=K4000 invested at 9%, and K4000 invested at 6%. ☺☺☺☺ \n" ); document.write( " |