document.write( "Question 1048234: Washers are \"punched\" from strips of sheet iron. \r
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document.write( "Washer description: \r
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document.write( "5/16\" inside diameter.
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document.write( "3/4\" outside diameter. \r
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document.write( "Iron description: \r
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document.write( "18 gauge.
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document.write( "3' length, 1\" width.
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document.write( "Weighs 2 lbs. per sq. ft. \r
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document.write( "The first washer is \"punched\" 1/8\" from the end, and each consecutive one is 1/16\" apart. \r
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document.write( "Determine: 1) Weight of 1000 washers, 2) Number of full strips required. \r
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document.write( "Not sure how to solve. Thanks. \n" );
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Algebra.Com's Answer #663813 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Find the area of each washer: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Area =~ 0.365087 sq inches \n" ); document.write( "--- \n" ); document.write( "Area of 1000 washers = 365 sq inches = 365/144 = 2.535 sq feet \n" ); document.write( "Weight of 1000 washers = area*2 = 5.07 pounds \n" ); document.write( "---- \n" ); document.write( "Iron description: \n" ); document.write( " 18 gauge. \n" ); document.write( " 3' length, 1\" width. \n" ); document.write( "-------- \n" ); document.write( "3' = 36 inches. \n" ); document.write( "36\" - 1/8\" = 35 7/8\" = 287/8 inches = 574/16\". \n" ); document.write( "Center to center of washers is 3/4 + 1/16 = 13/16 inches \n" ); document.write( "(574/16)/(13/16) = 44.15 --> 44 washers per sheet. \n" ); document.write( "--------- \n" ); document.write( "If you mean sheets needed for 1000 washers: \n" ); document.write( "1000/44 = 22.73 --> 23 sheets \n" ); document.write( "=================================================== \n" ); document.write( "PS Never heard of \"sheet iron.\" \n" ); document.write( "Sheet steel, but not sheet iron. \n" ); document.write( " |