document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13239>Question 13239</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the sum of four consecutive even integers is less than 250, what is the greatest possible value for one of these even integers? Explain your procedure.\r<BR>\n" );
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document.write( "Thank you...p.s this is due tomorrow in school for me:( </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6638 by </B><A HREF=/tutors/aboutme.mpl?userid=bam878s><B>bam878s(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bam878s><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi. Let x = an even integer.  Let's first examine an equation equal to 250.  We have, x + (x+2) + (x+4) + (x+6) = 250.  So x+x+2+x+4+x+6=260.  Adding like terms, we have 4x+12=250.  Solving this equation for x: 4x+12-12=250-12 leads to 4x=238.  Now, dividing by 4 on both sides yields x=59.5.  Now when x = 60 the sum of these for consecutive even integers will be greater than 250. So, the first even integer \"down\" from 59.5 is 58.  We have 58 + 60 + 62 + 64 = 244.  The greatest possible value for one of these integers is 64. </SPAN>\n" );
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