document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1048078>Question 1048078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ken is 2 more years than 14 times Mark's age. Ashley's age is 1 years less than twice Mark's age. If the sum of their ages are 35, then what are each child's age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #663737 by </B><A HREF=/tutors/aboutme.mpl?userid=vyshu544><B>vyshu544(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vyshu544><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vyshu544><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=663737\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> given, let marks age be 'x'<BR>\n" );
document.write( "       ken age is      2+14x<BR>\n" );
document.write( "       aslye age is    2x-1<BR>\n" );
document.write( "  <BR>\n" );
document.write( "    now,sum (addition) of all the three ages is 35<BR>\n" );
document.write( "       so;<BR>\n" );
document.write( "          x+2+14x+2x-1 = 35<BR>\n" );
document.write( "       <BR>\n" );
document.write( "             17x+1  =  35<BR>\n" );
document.write( "          ( adding -1 on both sides )\r<BR>\n" );
document.write( "\n" );
document.write( "           17x = 35-1<BR>\n" );
document.write( "            17x=34<BR>\n" );
document.write( "            x = 34/17<BR>\n" );
document.write( "           thereore the value of x is 2<BR>\n" );
document.write( "               so mark age is = 2<BR>\n" );
document.write( "                   ken age is 2+14(2) = 30<BR>\n" );
document.write( "                  aslye age is 2(2)-1 =  3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );