document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91403>Question 91403</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0078228948/algebrahomeworkh>Glencoe Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> pg. 166. One of two complementary angles measures 30 degrees more than three times the other. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66373 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=90 OR X=90-Y<BR>\n" );
document.write( "X=3Y+30 NOW SUBSTITUTE (90-Y) FOR X & SOLVE FOR Y<BR>\n" );
document.write( "90-Y=3Y+30<BR>\n" );
document.write( "-Y-3Y=30-90<BR>\n" );
document.write( "-4Y=-60<BR>\n" );
document.write( "Y=-60/-4<BR>\n" );
document.write( "Y=15 ANSWER.<BR>\n" );
document.write( "X=3*15+30<BR>\n" );
document.write( "X=45+30<BR>\n" );
document.write( "X=75 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "15+75=90<BR>\n" );
document.write( "90=90<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );