document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1048111>Question 1048111</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An architect designs a rectangular flower garden such that the width is exactly 2/3 of the length. If 380 feet of antique Picket fencing are to be used to enclose the garden, find the dimensions of the garden </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #663716 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=663716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Width = 2/3 Length<BR>\n" );
document.write( "and<BR>\n" );
document.write( "2L+2W = Perimeter Substitute with what we know:<BR>\n" );
document.write( "2L+2(2/3L) = 380<BR>\n" );
document.write( "2L+4/3L = 380 Put both numbers on the left over a common denominator<BR>\n" );
document.write( "6/3L+4/3L = 380<BR>\n" );
document.write( "10/3L = 380 divide both sides by 10/3<BR>\n" );
document.write( "L = 380*3/10 = 114 is the length, and the width:<BR>\n" );
document.write( "W = 2/3L = 2/3*114 = (2*114)/3 = 76 is the width<BR>\n" );
document.write( ">>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>><BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "2L+2W = Perimeter<BR>\n" );
document.write( "2(114)+2(76) = 380<BR>\n" );
document.write( "228+152 = 380 Correct (add the left, you get 380 as you should)<BR>\n" );
document.write( ":<BR>\n" );
document.write( "John<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );