document.write( "Question 1048116: Benjamin and associates, A real estate developer recently built 210 condos. The condos are either two bedroom units or three bedroom units . If the total number of rooms in the entire complex is 535 how many two bedroom units are there? How many three-bedroom? \n" ); document.write( "
Algebra.Com's Answer #663681 by macston(5194)\"\" \"About 
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(If you mean there are 535 bedrooms total)
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\n" ); document.write( "x=number of two bedroom; y=number of three bedroom
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\n" ); document.write( "x+y=210
\n" ); document.write( "x=210-y Use this to substitute for x
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\n" ); document.write( "2x+3y=535 Substitute for x from above
\n" ); document.write( "2(210-y)+3y=535
\n" ); document.write( "420-2y+3y=535 Subtract 420 from each side
\n" ); document.write( "y=115
\n" ); document.write( "ANSWER 1: There were 115 three bedroom condos
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\n" ); document.write( "x=210-y
\n" ); document.write( "x=210-115
\n" ); document.write( "x=95
\n" ); document.write( "ANSWER 2: There were 95 two bedroom condos
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\n" ); document.write( "CHECK:
\n" ); document.write( "2x+3y=535
\n" ); document.write( "2(95)+3(115)=535
\n" ); document.write( "190+345=535
\n" ); document.write( "535=535
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