document.write( "Question 1048113: find the restriction value of x. -11/25x
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Algebra.Com's Answer #663680 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "If the expression is \"-11%2F%2825x%29\", then you set the denominator equal to zero. Then solve for x.\r
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\n" ); document.write( "\n" ); document.write( "\"25x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"25x%2F25=0%2F25\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=0\"\r
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\n" ); document.write( "\n" ); document.write( "So if \"x+=+0\" then the denominator is zero. To avoid division by zero errors, we must restrict x to not be equal to zero. It can equal any other number.\r
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\n" ); document.write( "\n" ); document.write( "So the restriction would be written as \"x%3C%3E0\" (x cannot be equal to zero)\r
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