document.write( "Question 1048069: What makes this statement false? \r
\n" ); document.write( "\n" ); document.write( "if $\"+f%28x%29+=+x+%2B+1+\"$ and $\"+g%28x%29+=+6x+\"$ then (f ○ g)(x) = (g ○ f) $\"+%28x%29+\"$ \n" ); document.write( "

Algebra.Com's Answer #663640 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
What makes this statement false? \r
\n" ); document.write( "\n" ); document.write( "if f(x) = x + 1 and g(x) = 6x then (fog)(x) = (gof)(x)
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\n" ); document.write( "fog(x) = f[g(x)] = f(6x) = 6x+1
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\n" ); document.write( "gof(x) = g[f(x)] = g(x+1) = 6(x+1) = 6x+6
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\n" ); document.write( "Ans: 6x+1 is not equal to 6x+6
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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