document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1048050>Question 1048050</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I do not know how to solve this problem: Find three consecutive integers, such that the sum of the largest and twice the smallest is 41.  I know that  the first number will be represented by x.  I also know that 41 comes after the equals sign. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #663617 by </B><A HREF=/tutors/aboutme.mpl?userid=advanced_Learner><B>advanced_Learner(501)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=advanced_Learner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=advanced_Learner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=663617\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+x+1+x+2\r<BR>\n" );
document.write( "\n" );
document.write( "x+2 +  2x=41<BR>\n" );
document.write( "3x=39<BR>\n" );
document.write( "x=13\r<BR>\n" );
document.write( "\n" );
document.write( "13 14 15 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );