document.write( "Question 1048050: I do not know how to solve this problem: Find three consecutive integers, such that the sum of the largest and twice the smallest is 41. I know that the first number will be represented by x. I also know that 41 comes after the equals sign. \n" ); document.write( "

Algebra.Com's Answer #663616 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let the consecutive integers be:
\n" ); document.write( " $\"+n+\"$ , $\"+n%2B1+\"$ , and $\"+n%2B2+\"$
\n" ); document.write( "------------------------------
\n" ); document.write( " $\"+n%2B+2+%2B+2n+=+41+\"$
\n" ); document.write( " $\"+3n+=+39+\"$
\n" ); document.write( " $\"+n+=+13+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+n+%2B+1+=+14+\"$
\n" ); document.write( " $\"+n+%2B+2+=+15+\"$
\n" ); document.write( "----------------
\n" ); document.write( "The numbers are 13, 14, and 15
\n" ); document.write( "----------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+n%2B+2+%2B+2n+=+41+\"$
\n" ); document.write( " $\"+15+%2B+2%2A13+=+41+\"$
\n" ); document.write( " $\"+15+%2B+26+=+41+\"$
\n" ); document.write( " $\"+41+=+41+\"$
\n" ); document.write( "OK \n" ); document.write( "

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