document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1047973>Question 1047973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 90<BR>\n" );
document.write( "&#8203;% <BR>\n" );
document.write( "antifreeze solution must be mixed with 100<BR>\n" );
document.write( " <BR>\n" );
document.write( "gallons of 25<BR>\n" );
document.write( "&#8203;% <BR>\n" );
document.write( "antifreeze to get a mixture that is 80<BR>\n" );
document.write( "&#8203;% <BR>\n" );
document.write( "&#8203;antifreeze? Use the&#8203; six-step method. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #663521 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=663521\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the amount of 90% solution:<BR>\n" );
document.write( "0.90x+0.25(100) = 0.80(100+x)<BR>\n" );
document.write( "0.90x+25 = 80+0.80x<BR>\n" );
document.write( "0.10x = 55<BR>\n" );
document.write( "x = 550 gallon </SPAN>\n" );
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