document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1047963>Question 1047963</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square is given with sides, s. In a rectangle, one dimension is two more than s and the other dimension is four more than s. If the perimeter of the rectangle is 24, find the area of the square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #663515 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=663515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = 2s<BR>\n" );
document.write( "y = 4s<BR>\n" );
document.write( "Perimeter = 2L+2W = 24<BR>\n" );
document.write( "2(4s)+2(2s) = 24<BR>\n" );
document.write( "8s+4s = 24<BR>\n" );
document.write( "12s = 24<BR>\n" );
document.write( "s = 2<BR>\n" );
document.write( "Area of the square: s^2 = 2^2 = 4 </SPAN>\n" );
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