document.write( "Question 1047906: Here is the question:\r
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document.write( "A man has $8000 invested, part at 4% and the rest at 2.5%. The annual income from the 4% investment is $34 more than that from the 2.5% investment. How much is invested at 4%? \n" );
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Algebra.Com's Answer #663487 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! x, How much is invested at 4%.\r \n" ); document.write( "\n" ); document.write( ".04x - 34 = .025(8000 - x) \n" ); document.write( ".065x = 234 \n" ); document.write( "x = 234/.06 = $3600, How much is invested at 4%. \n" ); document.write( " |