document.write( "Question 1047922: Average daily prices are expected to be $400 with a standard deviation of $6.50.\r
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document.write( "What can a person expect in what range will the price be 68% of the time? 95% of the time? What does he have to assume? \n" );
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Algebra.Com's Answer #663486 by ewatrrr(24785) You can put this solution on YOUR website! one standard deviation from the mean accounts for about 68% of the set \n" ); document.write( "two standard deviations from the mean account for about 95% \n" ); document.write( "and three standard deviations from the mean account for about 99.7%. \n" ); document.write( "What can a person expect in what range will the price be 68% of the time \n" ); document.write( "400 - 6.50 to 400 + 6.50 \n" ); document.write( " | \n" ); document.write( "What can a person expect in what range will the price be 95% of the time \n" ); document.write( "400 - 13.00 to 400 +13.00 \n" ); document.write( " |