document.write( "Question 1047914: A 26 ft piece of rope is cut into three pieces such that the second piece is twice the first piece and the third piece is 4ft less than 3 times the first piece. Find the length of the third piece \n" ); document.write( "
Algebra.Com's Answer #663482 by stanbon(75887)\"\" \"About 
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A 26 ft piece of rope is cut into three pieces such that the second piece is twice the first piece and the third piece is 4ft less than 3 times the first piece. Find the length of the third piece
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\n" ); document.write( "Let the pieces be f,s,t (1st,2nd,3rd)
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\n" ); document.write( "Equations:
\n" ); document.write( "f + s + t = 26 ft
\n" ); document.write( "s = 2f
\n" ); document.write( "t = 3f-4
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\n" ); document.write( "Substitute to solve for \"f\"::
\n" ); document.write( "f + 2f + 3f-4 = 26
\n" ); document.write( "6f = 30
\n" ); document.write( "first = 5 ft
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\n" ); document.write( "Ans: third = t = 3f-4 = 11 ft
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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