document.write( "Question 1047747: Chocolates were equally distributed in a class of girls. Had there been 20 girls more each would have received one chocolate less. and had there been 20 girls less each would have received 3 chocolates more. find the no of girls in the class and no. of chocolates received by each girl.
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Algebra.Com's Answer #663283 by ikleyn(52832)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Chocolates were equally distributed in a class of girls. Had there been 20 girls more each would have received one chocolate less. \n" ); document.write( "And had there been 20 girls less each would have received 3 chocolates more. \n" ); document.write( "Find the no of girls in the class and no. of chocolates received by each girl. \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let G = the number of girls in the class and C = the number of chocolates received by each girl.\r\n" ); document.write( "\r\n" ); document.write( "Then\r\n" ); document.write( "\r\n" ); document.write( "(G+20)*(C-1) = GC (1) (\"Had there been 20 girls more each would have received one chocolate less\")\r\n" ); document.write( "(G-20)*(C+3) = GC (2) (\"had there been 20 girls less each would have received 3 chocolates more\")\r\n" ); document.write( "\r\n" ); document.write( "We have to equations in two unknowns, but the equations are non-linear.\r\n" ); document.write( "Simplify each of the equations. Equation (1) becomes \r\n" ); document.write( "\r\n" ); document.write( "GC + 20C - G - 20 = GC, or, canceling GC in both sides,\r\n" ); document.write( "20C - G - 20 = 0, or\r\n" ); document.write( "20C - G = 20. (3)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Equation (2) becomes \r\n" ); document.write( "\r\n" ); document.write( "GC - 20C +3G - 60 = GC, or, canceling GC in both sides,\r\n" ); document.write( "-20C + 3G - 60 = 0, or\r\n" ); document.write( "-20C + 3G = 60. (4)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Now we have an equivalent system of two equations (3) and (4) in two unknowns, but this time the equations are linear.\r\n" ); document.write( "\r\n" ); document.write( "Add the equation (3) and the equation (4) (both sides). You will get\r\n" ); document.write( "\r\n" ); document.write( "2G = 20 + 60 = 80 ---> G = \n" ); document.write( " \n" ); document.write( " |