document.write( "Question 1047695: Juan Carlos traveled to the town square and back. The trip there took 3 hours and the trip back took 4 hours. If he averages 32 mph on the trip back, what speed of the average on the trip there? \n" ); document.write( "

Algebra.Com's Answer #663262 by josgarithmetic(39620) $\"\"$ $\"About$

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Trip going was at a faster speed, R. Trip back was at lower speed r. Variables also shown as assigned assumed.\r
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document.write( "                    SPEED        TIME        DISTANCE\r\n" );
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document.write( "GOING                 R            x           d\r\n" );
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document.write( "RETURN                r            y           d\r\n" );
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\n" ); document.write( "\n" ); document.write( "Basic constant travel rate rule is RT=D relating speed, time, distance.\r
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document.write( "R=unknownSpeedGoing\r\n" );
document.write( "d=unknownDistanceOneWay\r\n" );
document.write( "r=32\r\n" );
document.write( "x=3\r\n" );
document.write( "y=4\r\n" );
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\n" ); document.write( "\n" ); document.write( " $\"highlight_green%28Rx=ry%29\"$ ------because you could simply equate two expressions for d.\r
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\n" ); document.write( "\n" ); document.write( "ONE STEP ONLY
\n" ); document.write( " $\"highlight%28R=ry%2Fx%29\"$ ----------symbolic answer.\r
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\n" ); document.write( "\n" ); document.write( "Substitute the given values and evaluate R. \n" ); document.write( "

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