document.write( "Question 1047690: TV's are measured by the length of their diagonals. The ratio of a TV's length to width is 4:3 and its size is 55 inches. What is the perimeter around the TV? \n" ); document.write( "
Algebra.Com's Answer #663230 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "The ratio is 4:3 which means the width is 4x and the height is 3x where x is some positive number\r
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\n" ); document.write( "\n" ); document.write( "Draw the diagonal on the rectangular tv image. You'll see a right triangle forming. \r
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\n" ); document.write( "\n" ); document.write( "The legs of this triangle are 4x and 3x. The hypotenuse is 55. So,
\n" ); document.write( "a = 4x
\n" ); document.write( "b = 3x
\n" ); document.write( "c = 55\r
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\n" ); document.write( "\n" ); document.write( "Let's use the pythagorean theorem to solve for x.\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2+%2B+b%5E2+=+c%5E2\"
\n" ); document.write( "\"%284x%29%5E2+%2B+%283x%29%5E2+=+55%5E2\"
\n" ); document.write( "\"16x%5E2%2B9x%5E2+=+3025\"
\n" ); document.write( "\"25x%5E2+=+3025\"
\n" ); document.write( "\"%2825x%5E2%29%2F25+=+3025%2F25\"
\n" ); document.write( "\"x%5E2+=+121\"
\n" ); document.write( "\"sqrt%28x%5E2%29+=+sqrt%28121%29\"
\n" ); document.write( "\"x+=+11\" or \"x+=+-11\"
\n" ); document.write( "Ignore the negative x value. Recall that x must be positive.\r
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\n" ); document.write( "\n" ); document.write( "So we know that x = 11 now. Let's use this to find the width and height\r
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\n" ); document.write( "\n" ); document.write( "width = 4*x = 4*11 = 44
\n" ); document.write( "height = 3*x = 3*11 = 33\r
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\n" ); document.write( "\n" ); document.write( "This tv has a width of 44 inches (horizontal) and height of 33 inches (vertical)\r
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\n" ); document.write( "\n" ); document.write( "Add up all the sides of the rectangle to get: 44+33+44+33 = 154\r
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\n" ); document.write( "\n" ); document.write( "The perimeter is 154 inches
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